A generalization Brianchon's theorem

Let A1,A2,A3,A4,A5,A6 lie on a circle (O). Let A be a point on the plane. The perpendicualar of AAi at Ai meets the perpendicular of AAi+1 at Ai+1 at Bi, A7≡A1. Then B1B4,B2B5,B3B6 are concurrent
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Đào Thanh Oai —

 
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Activity
Tags
brianchon  circle  collinear  concyclic  cyclic  dao  midpoints  oai  pascal  perpendicular  quadrilateral tangential thanh thebault theorem triangle Show More…
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19+
Language
English (United Kingdom)
 
 
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4.4
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