A way conctruct circle of Thebault Theorem

Let ABC be a triangle, C1 on BC. E' is center of excircle of the triangle ABC1 respectively with B. I is incircle of the triangle ABC. Circle (AIE') meets (ABC) again at T. OT meets C1E' at N. Then N is center of circle tangent AC1,BC and circumcircle (ABC). Where O is circumcenter of ABC

 

Đào Thanh Oai

 
Material Type
Activity
Tags
thebault  theorem  away  collinear  concurrent  perpendicular 
Target Group (Age)
19+
Language
English (United Kingdom)
 
 
GeoGebra version
4.2
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980
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