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Exercise 2.17 - Perpendicular from a point on the line (with rusty compass)
Auteur :
Gianluca Occhetta
5 circles + 1 line = 6 steps (par 6)
GeoGebra
The triangle CBF is equilateral by Construction 2.16, hence the triangles CAF and BAF are congruent by (I.8)
Nouvelles ressources
Midpoint Theorem (V2): Integer Solutions
Isosceles Right Triangle
Midpoint Theorem Questions: Mild
Conditional Probability in Two-Way Tables
Odd Function Explorer
Découvrir des ressources
Triangle
Tangent To A Parabola
三角函数变换
lamp, Tiziana and Sophie
Pi visualisatie
Découvrir des Thèmes
Somme de Riemann
Intégrale Définie
Prisme
Inégalités
Fonctions Exponentielles