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Exercise 2.17 - Perpendicular from a point on the line (with rusty compass)
Autor:
Gianluca Occhetta
5 circles + 1 line = 6 steps (par 6)
GeoGebra
The triangle CBF is equilateral by Construction 2.16, hence the triangles CAF and BAF are congruent by (I.8)
Nuevos recursos
အခြေခံ data အခေါ်အဝေါ်များ
functionartculture
Variation Theory Illustration: Point-Slope Form
Involute of the Circle
Intersections of y=a^x and y=log(a, x)
Descubrir recursos
sine curve exploration
cometa_sen
Ellipse Lab
Further Disc Ex 1
Tangent to a Circle
Circumcenter- Courtney Harrison
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Intersección
Triángulos Equiláteros
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