Hipérbole x² / 4 - y² / 9 = 1

Author:
Adelmo Ribeiro de Jesus
Topic:
Hyperbola
Neste caso, a=2 e b=3 e c^2=a^2+b^2=13. Os focos são F1=(-sqr(13), 0) e F2=(sqr(13), 0)
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