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Neuberg cubic (K001)

We construct triangle and then K001 cubic. After that we take point which can be any point from the cubic then we cojugate that point isogonal and we get point which is also on the same cubic. And by using GeoGebra we conclude that K001 is isogonal transformed of itself.

Barycentric equation

Proof

Let the barycentric coordinates of a point are , and . The barycentric coordinates of its isogonal conjugate are , , or , and . And now we substitude , and in the equation with , and . In this we get the same equqtion as that in the beginig and this means that Neuberg cubic is isogonal transform of itself.