Solve a compound inequality
Solve[-2 < x + 3 < 5, x]
Use assignments and rewrite
a := x + 3
Solve[-2 < a < 5, x]
Solve and Deconstruct
Solve[2 < (3x - 1)/2 < 5, x]
Then define:
ineq := (3x - 1)/2
And solve piece by piece:
Solve[ineq > 2, x]
Solve[ineq < 5, x]
Does solving each part individually give the same result as the combined version?