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追赶曲线-复数

Author:i景然
20260802 #来源https://tieba.baidu.com/p/7255896046 #复数绘图 c = 0.8 + 0.8ί P = 描点(多边形(序列(c ί^k, k, 0, 3))) n = 20 b = P / c l1 = 序列(序列(c ί^j b^k, j, 0, 3), k, 0, n) l2 = 映射(多边形(s), s, l1) l3=l2

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