# PERMUTATIONS & COMBINATIONS -2

A bag contains 5 black and 6 red balls. Determine the number of ways in which
2 black and 3 red balls can be selected.

There are 5 black and 6 red balls in the bag.
2 black balls can be selected out of 5 black balls in ways and 3 red balls can be selected out of 6 red balls in ways.
Thus, by Fundamental principle of counting , required number of ways of selecting 2 black and 3 red balls
= ways = 10 20 = 200 ways.

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