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IMO 2014/P4 - addendum
Autor:
Nikolaos Rapanos
ADOE IS #, K is its center and it also lies on DE; therefore KA = KH = KO, hence OH is perpendicular to AH
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Special Right Triangles 30°-60°-90° and 45°-45°-90°
အခြေခံ data အခေါ်အဝေါ်များ
Tracing r = 2 cos(θ)
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