Triple Integrals
Triple integrals
Consider defined on a closed and bounded domain in . Then can be contained in a cuboid . We divide the cuboid into small sub-cuboids by planes parallel to xy, yz, and xz planes. Choose the small sub-cuboids that are contained in and label them from to . For the sub-cuboid, we denote its side lengths to be , and . Then its volume is . Moreover, we select an arbitrary point in the sub-cuboid.
The triple integral of over is defined to be the limit of the following "Riemann sum":
The diagram shown below is the limiting procedure of cutting the domain into smaller and smaller sub-cuboids.

Physical interpretation of triple integral
Suppose is a 3D solid and its density varies at different points of the solid according to . Then Total mass of .
In particular, if , i.e. the solid has "uniform density" of 1, we can regard the triple integral as the volume of the solid.
Suppose , i.e. a cuboid. We can calculate the triple integral using the following version of Fubini's theorem:
Fubini's theorem: Suppose and . Then we have
This integral is also equal to any of the other five possible orderings for the iterated triple integral.
Example: Find the value of , where .
Answer:
Exercise: Find the mass of the cuboid with density .
Triple integrals over a general domain
Suppose is defined on a domain , which is solid bounded by the graph of from below and by the graph of from above over a region on the xy plane. In other words, for all in . This kind of domains is called a simple xy-solid. We can reduce the triple integral over a simple xy-solid to the double integral as follows:
Moreover, if is a Type I region bounded from below by the graph of and from above by the graph of over , we can express the triple integral as the following iterated integral:
We have similar results for simple xz-solid and simple yz-solid:
is a simple xz-solid if it is bounded by the surfaces and over the region on xz plane and for all in . Then the triple integral over is as follows:
(The definition of simple yz-solid and its analogous result are left as exercise.)
Example: Let be the wedge in the first octant i.e. the set of points in such that x,y,z coordinates are non-negative, that is cut from the cylindrical solid by the planes and . Find the value of the triple integral .
Answer:
The domain can be regarded as a simple xy-solid such that it is bounded by the cylinder from above and the plane from below over a triangular region as shown in the applet below. Notice that
(Note: Positive square root is used because is non-negative)
Then, we have
Moreover, can be regarded as a Type II region bounded by and . Therefore, we can express the triple integral as the following iterated integral:
Exercise: Express the triple integral in the above example as an iterated integral by regarding as a simple yz-solid. You are not required to compute the iterated integral.
Example: Find the volume of the solid bounded by the two paraboloids and .
Answer:
Volume of can be computed by evaluating the triple integral . And can be regarded as a simple xz-solid bounded by and . In order to find the region on which the solid is bounded by these two surfaces, we need to find the projection of the intersection of these two surfaces to the xz plane.
First, we combine the two equations of the surfaces. We have
i.e., the projection of the intersection onto xz plane is a ellipse, as shown in the applet below. Therefore, is the region bounded by the ellipse, which can be regarded as a Type I region bounded by and for . Hence, we can write the triple integral as the following iterated integral:
(Note: Use substitution )
Changing the order of integration
Sometimes it is necessary to change the order of integration in an iterated integral so that the it can be evaluated more easily.
Example: Suppose is a 3D solid such that
Describe the solid and then change the order of integration in the iterated integral to evaluate the triple integral.
Answer:
Since the innermost integral is with respect to , the solid is a simple yz-solid bounded by and . Moreover, the integrals with respect to and suggest that the simple yz-solid is over the region on yz plane, where is the region bounded by and for . The applet below shows that is a tetrahedron bounded by four planes: , , , and .
We can view as a simple xz-solid bounded by and over the triangular region bounded by and for . Therefore, we can write the iterated integral in a different order as follows:
Exercise: Evaluate the following iterated integral by reiterating it in a different order. . (Note: You will need to make a good sketch of the region.)