Law of Sines

Start with ABC and circumscribe it about a circle with center at O and with radius equal to R units. Draw in the diameter CJ and the chord BJ. <CBJ is a right angle, since it is inscribed in a semicircle. Therefore in both figures, In the first diagram <J=<A because they are both inscribed in the same arc of the circle. In the second diagram <J=180-<A, because opposite angles of an inscribed quadrilateral are supplementary. Remember that --> in both figures. Therefore, --> The same procedure applied to the other angles of ABC yields and Combining these results we get the extended Law of Sines, For a triangle ABC with circumradius R,