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Problem 2
Autor:
Tom Ku
With square ABCD, CE parallel to BD, and DE = DB. To Prove: BF = BE
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Area Between Two Curves
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construction 16
LV.VO.2015.10.4
Parallelogram Diagonals Theorem
Angle Bisector, Perpendicular Bisector and Median
Fractions on a Number Line
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