# Villalpando's proportionatrix prima

- Author:
- RMF

Construction of the

*proportionatrix prima*in a semicircle of diameter AG. Steps to find a point K of the curve from a point F of the semicircle:- Semicircle of diameter AG and center D (see diagram).
- Semicircle of diameter DG.
- A point F on the large semicircle is selected and FG is drawn cutting the small semicircle in H.
- Circle of center G and radius GH.
- I is the intersection of AG with this circle.
- Circle of center I and radius IG.
- K is the intersection of this circle and FG.
- CK is perpendicular to AG.

Once the curve has been drawn, it is easy to prove that AG/GF = GF/GK = GK/GC: it is enough to show that AGF, MFK and GKD are similar triangles, and that GF = GM. This statement is proved in Villalpando's proposition X http://www.e-rara.ch/zut/content/pageview/3800973.
Villalpando's

*proportionatrix prima*can be used to find two mean proportional between lines*a,b*, with*a>b*. If we set AG =*a*and the*proportionatrix prima*is met by the straight line drawn from the extreme C of GC =*b*perpendicular to AG, then GF and GK are the two mean proportional of AG and GC (Villalpando's actual use of this curve to find the two mean proportionals between two assigned straight lines is a bit different, still is equivalent to the one just expounded).