Pythagoras Theorem
Proof of Pythagoras theorem c2 = a2 + b2
- We will prove the Pythagoras Theorem on the ABC triangle through a square approach.
- It is known that c 2 (square ABIH) is a flat area that represents a square with a side length c on the hypotenuse of a right angle triangle, as well as a 2 (square ACFG) and b 2 (square BCED).
- We will prove whether the area of the square with an area of c2 (square ABIH) will be equal to the area of the squares a2 (square ACFG) and b2 (square BCED) which proves the formula c2 = a2 + b2