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難問1A
Author:
Bunryu Kamimura
よって、△BEHは直角二等辺三角形になる。
GeoGebra
New Resources
正17角形 作図 regular 17-gon 2
6章⑥三角柱の展開図
二次曲線と離心率
standingwave
standingwave-reflection-free
Discover Resources
有界の定義(数列)
chime
Secret Star
自由落下
平均変化率と微分係数
Discover Topics
Difference and Slope
Boxplot
Cube
Median Line
Rhombus