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難問1A
Author:
Bunryu Kamimura
よって、△BEHは直角二等辺三角形になる。
GeoGebra
New Resources
standingwave-plus
接点の作る円は内接円
対数螺旋
standingwave-reflection-free
直線の軌跡
Discover Resources
三角錐の重心 The center of gravity of the triangular pyramid
直方体の最短経路
数学Ⅲ回転体&体積MT01
瞬間の速さ
はめこみ図形
Discover Topics
Matrices
Perimeter
Special Points
Hyperbola
Scatter Plot