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難問1A

Author:Bunryu Kamimura

よって、△BEHは直角二等辺三角形になる。

New Resources

  • standingwave-reflection-fixed
  • コイン投げと樹形図
  • 正17角形 作図 regular 17-gon
  • standingwave
  • 対数螺旋

Discover Resources

  • 側面図は?
  • 正十二面体辺切り
  • 定義域内の最大最小
  • 底面が正方形の四角錐
  • 中点連結定理

Discover Topics

  • Circumcircle or Circumscribed Circle
  • Kite
  • Geometric Mean
  • Area
  • Vectors 3D (Three-Dimensional)
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