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S4 Circle Theorems
S.5 Ch.10 Equal Angles, Equal Arcs, Equal Chords
S.5 Ch.10 Arcs proportional to angles centre
Arcs Proportional to Angles at the Centre(弧長與圓心角成比例)
Radius perpendicular to chord
Chord perpendicular to radius
Equidistant chord of a circle are equidistant from the cente
Angle at Centre & Angle at Circumference: Proof 圓心角與圓周角：証明
Angles in the same Segment (Proof)
Angle in a Semi-circle 2
Angle at semi circle
opposite angles, cyclic quadrilateral
Exterior angles of cyclic quadrilateral
Testing Concyclic
make 4 points concyclic
Tangent perpendicular to radius
Tangent Properties
Alternate Segment Theorem
Converse of angle in alternate segment
Intersecting Circles
Power of a Point
The Secant Theorem
4 centers of triangles and euler line
S4 Circle Theorems
Författare/skapare:
tkyggb
Circle Theorems
S.5 Ch.10 Equal Angles, Equal Arcs, Equal Chords
S.5 Ch.10 Arcs proportional to angles centre
Arcs Proportional to Angles at the Centre(弧長與圓心角成比例)
Radius perpendicular to chord
Chord perpendicular to radius
Equidistant chord of a circle are equidistant from the cente
Angle at Centre & Angle at Circumference: Proof 圓心角與圓周角：証明
Angles in the same Segment (Proof)
Angle in a Semi-circle 2
Angle at semi circle
opposite angles, cyclic quadrilateral
Exterior angles of cyclic quadrilateral
Testing Concyclic
make 4 points concyclic
Tangent perpendicular to radius
Tangent Properties
Alternate Segment Theorem
Converse of angle in alternate segment
Intersecting Circles
Power of a Point
The Secant Theorem
4 centers of triangles and euler line
Nästa
S.5 Ch.10 Equal Angles, Equal Arcs, Equal Chords
Nya resurser
画直线等分三角形的面积
兩位數除以一位數（二）
第八周作业
兩位數加法
【案例】2018年全国1卷理科12题
Upptäck resurser
這是我的答案
Percentage
根據百分率找數量（二）: 例3
perd fr ctr bisect
PTCCS2new2
Undersök matematisk områden
Likformiga trianglar
Cosinus
Pythagoras eller Pythagoras sats
Matematik
Prisma
